I have a tube that is open at one end and close at the other, and is 1 meter long. How do you calculate the three lowest frequencies of sound that produce resonance in the tube?
Wave length and frequency are inversions.
The average speed of sound is 343 meters per second.
A 1 meter wavelength then would be a frequency of 1/343 hertz.
A tube will produce most easily a wavelength equal to it's length. It can also produce a wave length of twice it's length.
All other tones will be some division of these lengths.
A 12 meter tube would produce wave lengths of 24m (twice the tube) 12m (equal), 6m (half), 4m (a third), 3m (a quarter), 2m (a sixth) etc. They will all will be completely divisible into the tube.
That makes frequencies of 12/343 Hz, etc.