Thread: How do I calculate changes in internal energy and Gibbs free energy in this problem?

10 grams of supercooled water at -10 degrees C freezes. The latent heat of fusion is lost to the surroundings and the ice regains the previous temperature.

I have already calculated the changes in enthalpy and entropy, but I'm not sure how to calculate the change in internal energy and Gibbs free energy.

For liquid and solid, internal energy, du equal to enthalpy, dh.
dh = du +d(pv) ~ du, dv~0

Gibbs Free energy.
?G = ?H - T?S