Thread: How do you calculate the standard enthalpy of combustion of diamonds?

1. How do you calculate the standard enthalpy of combustion of diamonds? var addthis_config = {"data_track_clickback":false};

How do you calculate if the Enthalpy of formation is 1.895?
How do you calculate if the Enthalpy of formation is +1.895?

is it +1.895 or -1.895 for combustion?

2. Weee! Diamonds are shiny!

3. i think combustion standard enthalpy is calculated the same as any reaction. if its just standard H u want then its just products - reactants at standard.

in this case, if you say diamonds H0 is 1.895 then:
1.895 - 0 (graphite is just carbon in its standard state, right?) = 1.895

this makes sense since diamonds are highly organized so change in entropy will be very very small meaning with gibs free energy formula
G = H - TS (delta g, h, s)
then in order for G to equal 0, H must = TS...S being very small. T would equal 1.895/very very small S = very high temperature T. and we all know diamonds are only formed under very high temperature and pressures. hope that helps =P

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